Archive for the ‘luxury yacht charter’ Category
The owner of a luxury motor yacht that sails among the 4000 Greek islands charges $450/person/day if exactly 20 people sign up for the cruise. However, if more than 20 people sign up (up to the maximum capacity of 90) for the cruise, then every fare is reduced by $4 for each additional passenger. Assume at least 20 people sign up for the cruise and let x denote the number of passengers above 20.
(a) Find a function R giving the revenue/day realized from the charter.
(b) What is the revenue/day if 41 people sign up for the cruise?
(c) What is the revenue/day if 76 people sign up for the cruise?
a.
Revenue= (20 + x ) (450 – 4x)
b.
Revenue= (20 + 41) (450 – 4 x 41)
Revenue= $17,446
c.
Revenue= (20+76) (450 – 76 x 4)
Revenue= $14,016
The owner of a luxury motor yacht that sails among the 4000 Greek islands charges $450/person/day if exactly 20 people sign up for the cruise. However, if more than 20 people sign up (up to the maximum capacity of 90) for the cruise, then every fare is reduced by $4 for each additional passenger. Assume at least 20 people sign up for the cruise and let x denote the number of passengers above 20.
(a) Find a function R giving the revenue/day realized from the charter.
(b) What is the revenue/day if 41 people sign up for the cruise?
(c) What is the revenue/day if 76 people sign up for the cruise?
a) R=450*20+summation(450-4(j+1))[j varies from 0 to x-1] where x<=70
R=9000+450*x – 4*(1+2+3+…..x)
R=9000+450x-4x(x+1)/2
R=9000+450x-2x(x+1)
b) here x is 21
R=450*20+(450-4)+(450-8)+(450-12)…+(450-84)
R=9000+450*21- 4*(1+2+…+21)
R=9000+9450-4*21*22/2=18450-44*21=18450-924=17526
c) here x is 56
R=9000+450*56-2*56*57
=9000+25200-6384=27816
Ok its kind of tough i think but it goes:
The owner of a luxury motor yacht that sails among the 4000 Greek islands charges $610/person/day if exactly 20 people sign up for the cruise. However, if more than 20 people sign up (up to the maximum capacity of 90) for the cruise, then every fare is reduced by $3 for each additional passenger. Assume at least 20 people sign up for the cruise and let x denote the number of passengers above 20.
then how would i find a function R giving the revenue/day realized from the charter?
Thank you so much!!!!!
(20+x)(610-3x)= revenue———— for example 5 persons above 20 then (20+5)($610-$3(5))= (25)($595)=$14,875